下面代码的执行结果是: ls = ["20", "2.0", "Python"] ls.append(20) ls.append([20, "20"]) print(ls)
A、['20','2.0','Python',20]
B、['20','2.0','Python',20,[20,'20']]
C、['20','2.0','Python',20,['20']]
D、['20','2.0','Python',20,20,'20']
发布时间:2024-08-30 12:17:06