过点(1,0,0),(0,1,0),且与曲面z=x2+y2相切的平面为() A、z=0与x+y-z=1B、z=0与2x+2y-z=1C、z=y与x+y-z=1D、x=y与2x+2y-z=1E、z=0与2x+2y-z=2 发布时间:2024-07-09 23:39:25