可使 ∂z∂x∂y=2x−y∂z∂x∂y=2x−y 成立的函数为
A、 z=x2y−xy22−5z=x2y−xy22−5;
B、z=x2y−xy32z=x2y−xy32;
C、z=x2y−xy22+ex+ey−5z=x2y−xy22+ex+ey−5;
D、z=x3y−xy22
发布时间:2024-11-06 15:01:12
A、 z=x2y−xy22−5z=x2y−xy22−5;
B、z=x2y−xy32z=x2y−xy32;
C、z=x2y−xy22+ex+ey−5z=x2y−xy22+ex+ey−5;
D、z=x3y−xy22